int i = 0 ;

static int a[] = { 0, 1, 2, 3, 4 } ;

void print_book ( struct t_book *b )
{
printf("The title is: %s\n", (*b).title ) ;
printf("The author is: %s\n", b->author ) ;
printf("The price is: %lf\n", b->value );
}

The "->" operator is dereferencing + selection (follow a pointer to a structure and take just one field of the structure)

char c1, c2, *p ;
p=&c ; /* p will point to the location of c */
c='a' ; /* c will take the value 'a' */
putchar(*p) ; /* the content of the location pointed by p will be printed */
p++ ; /* allowed but wrong in this context */
(*p)++ ; /* the content of the location pointed by p will be incremented*/
putchar(*p) ; /* see above */
c1 = *p ; /* the content of the location pointed by p will be copied in c1 */
c = p ; /* not allowed - type mismatch */
p = *c ; /* not allowed */
p = &c1 ; /* p will point to the location of c1 */

Observation 1:

by definition, the name of an array is the address of the first element
p = &(carray[0]) ; <=> p = carray ;

Observation 2:

p + i points to the i-th element of the array: p = p + i*sizeof(data type)
p + i will point

Draw a picture showing the situation in the memory after the execution of the following instructions. The picture should include all variables. You can assume that sizeof(int) = 2, sizeof(char) = 1 (in bytes).

char carray[ 16 ] = { "this is a string"} ;
char *p1 ;
int iarray[ 20 ], *p2 ;
p1 = carray ; p2 = iarray ;

p1 += 2 ;
*p1++ = 'a' ;
*p1 = 't' ;
*p2 = 5 ;